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Maximum Subarray Sum problem is to find the subarray with maximum sum. For example, given an array {12, -13, -5, 25, -20, 30, 10}, the maximum subarray sum is 45. The naive solution for this problem is to calculate sum of all subarrays starting with every element and return the maximum of all. We can solve this using Divide and Conquer, what will be the worst case time complexity using Divide and Conquer.
  • a)
    O(n)
  • b)
    O(nLogn)
  • c)
    O(Logn)
  • d)
    O(n^2)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Maximum Subarray Sum problem is to find the subarray with maximum sum....
Explanation:


The Divide and Conquer approach for the Maximum Subarray Sum problem divides the given array into two halves and recursively finds the maximum subarray sum in left half, right half, and the subarrays crossing the middle element. Finally, it returns the maximum of these three sums.




Worst Case Time Complexity:


The worst case for this approach occurs when the subarray with maximum sum crosses the middle element. In this case, the algorithm will have to check all the subarrays crossing the middle element. Since there are n subarrays crossing the middle element, and each subarray can be found in O(n) time, the total time complexity will be O(n^2) for this case.


However, if the subarray with maximum sum is entirely in either left or right half, then the algorithm will recursively find the maximum subarray sum in that half and return it. This case can be solved in O(nLogn) time complexity.




Therefore, the worst case time complexity of the Divide and Conquer approach for the Maximum Subarray Sum problem is O(nLogn).
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